30x^2+65x-315=0

Solution for 30x^2+65x-315=0 equation:

30x^2+65x-315=0

a = 30; b = 65; c = -315;
Δ = b2-4ac
Δ = 652-4·30·(-315)
Δ = 42025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{42025}=205$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-205}{2*30}=\frac{-270}{60}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+205}{2*30}=\frac{140}{60}
=2+1/3
$